Integrand size = 23, antiderivative size = 238 \[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\frac {11 b d^4 x}{8 c^3}+\frac {24 i b d^4 x^2}{35 c^2}-\frac {11 b d^4 x^3}{24 c}-\frac {12}{35} i b d^4 x^4+\frac {9}{40} b c d^4 x^5+\frac {2}{21} i b c^2 d^4 x^6-\frac {1}{56} b c^3 d^4 x^7-\frac {11 b d^4 \arctan (c x)}{8 c^4}+\frac {1}{4} d^4 x^4 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))+\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-\frac {24 i b d^4 \log \left (1+c^2 x^2\right )}{35 c^4} \]
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Time = 0.15 (sec) , antiderivative size = 238, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {45, 4992, 12, 1816, 649, 209, 266} \[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))+\frac {1}{4} d^4 x^4 (a+b \arctan (c x))-\frac {11 b d^4 \arctan (c x)}{8 c^4}-\frac {1}{56} b c^3 d^4 x^7+\frac {11 b d^4 x}{8 c^3}+\frac {2}{21} i b c^2 d^4 x^6+\frac {24 i b d^4 x^2}{35 c^2}-\frac {24 i b d^4 \log \left (c^2 x^2+1\right )}{35 c^4}+\frac {9}{40} b c d^4 x^5-\frac {11 b d^4 x^3}{24 c}-\frac {12}{35} i b d^4 x^4 \]
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Rule 12
Rule 45
Rule 209
Rule 266
Rule 649
Rule 1816
Rule 4992
Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} d^4 x^4 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))+\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-(b c) \int \frac {d^4 x^4 \left (70+224 i c x-280 c^2 x^2-160 i c^3 x^3+35 c^4 x^4\right )}{280 \left (1+c^2 x^2\right )} \, dx \\ & = \frac {1}{4} d^4 x^4 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))+\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-\frac {1}{280} \left (b c d^4\right ) \int \frac {x^4 \left (70+224 i c x-280 c^2 x^2-160 i c^3 x^3+35 c^4 x^4\right )}{1+c^2 x^2} \, dx \\ & = \frac {1}{4} d^4 x^4 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))+\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-\frac {1}{280} \left (b c d^4\right ) \int \left (-\frac {385}{c^4}-\frac {384 i x}{c^3}+\frac {385 x^2}{c^2}+\frac {384 i x^3}{c}-315 x^4-160 i c x^5+35 c^2 x^6+\frac {385+384 i c x}{c^4 \left (1+c^2 x^2\right )}\right ) \, dx \\ & = \frac {11 b d^4 x}{8 c^3}+\frac {24 i b d^4 x^2}{35 c^2}-\frac {11 b d^4 x^3}{24 c}-\frac {12}{35} i b d^4 x^4+\frac {9}{40} b c d^4 x^5+\frac {2}{21} i b c^2 d^4 x^6-\frac {1}{56} b c^3 d^4 x^7+\frac {1}{4} d^4 x^4 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))+\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-\frac {\left (b d^4\right ) \int \frac {385+384 i c x}{1+c^2 x^2} \, dx}{280 c^3} \\ & = \frac {11 b d^4 x}{8 c^3}+\frac {24 i b d^4 x^2}{35 c^2}-\frac {11 b d^4 x^3}{24 c}-\frac {12}{35} i b d^4 x^4+\frac {9}{40} b c d^4 x^5+\frac {2}{21} i b c^2 d^4 x^6-\frac {1}{56} b c^3 d^4 x^7+\frac {1}{4} d^4 x^4 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))+\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-\frac {\left (11 b d^4\right ) \int \frac {1}{1+c^2 x^2} \, dx}{8 c^3}-\frac {\left (48 i b d^4\right ) \int \frac {x}{1+c^2 x^2} \, dx}{35 c^2} \\ & = \frac {11 b d^4 x}{8 c^3}+\frac {24 i b d^4 x^2}{35 c^2}-\frac {11 b d^4 x^3}{24 c}-\frac {12}{35} i b d^4 x^4+\frac {9}{40} b c d^4 x^5+\frac {2}{21} i b c^2 d^4 x^6-\frac {1}{56} b c^3 d^4 x^7-\frac {11 b d^4 \arctan (c x)}{8 c^4}+\frac {1}{4} d^4 x^4 (a+b \arctan (c x))+\frac {4}{5} i c d^4 x^5 (a+b \arctan (c x))-c^2 d^4 x^6 (a+b \arctan (c x))-\frac {4}{7} i c^3 d^4 x^7 (a+b \arctan (c x))+\frac {1}{8} c^4 d^4 x^8 (a+b \arctan (c x))-\frac {24 i b d^4 \log \left (1+c^2 x^2\right )}{35 c^4} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 290, normalized size of antiderivative = 1.22 \[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\frac {11 b d^4 x}{8 c^3}+\frac {24 i b d^4 x^2}{35 c^2}-\frac {11 b d^4 x^3}{24 c}+\frac {1}{4} a d^4 x^4-\frac {12}{35} i b d^4 x^4+\frac {4}{5} i a c d^4 x^5+\frac {9}{40} b c d^4 x^5-a c^2 d^4 x^6+\frac {2}{21} i b c^2 d^4 x^6-\frac {4}{7} i a c^3 d^4 x^7-\frac {1}{56} b c^3 d^4 x^7+\frac {1}{8} a c^4 d^4 x^8-\frac {11 b d^4 \arctan (c x)}{8 c^4}+\frac {1}{4} b d^4 x^4 \arctan (c x)+\frac {4}{5} i b c d^4 x^5 \arctan (c x)-b c^2 d^4 x^6 \arctan (c x)-\frac {4}{7} i b c^3 d^4 x^7 \arctan (c x)+\frac {1}{8} b c^4 d^4 x^8 \arctan (c x)-\frac {24 i b d^4 \log \left (1+c^2 x^2\right )}{35 c^4} \]
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Time = 2.46 (sec) , antiderivative size = 190, normalized size of antiderivative = 0.80
method | result | size |
parts | \(d^{4} a \left (\frac {1}{8} c^{4} x^{8}-\frac {4}{7} i c^{3} x^{7}-c^{2} x^{6}+\frac {4}{5} i c \,x^{5}+\frac {1}{4} x^{4}\right )+\frac {d^{4} b \left (\frac {\arctan \left (c x \right ) c^{8} x^{8}}{8}-\frac {4 i \arctan \left (c x \right ) c^{7} x^{7}}{7}-\arctan \left (c x \right ) c^{6} x^{6}+\frac {4 i \arctan \left (c x \right ) c^{5} x^{5}}{5}+\frac {c^{4} x^{4} \arctan \left (c x \right )}{4}+\frac {11 c x}{8}-\frac {c^{7} x^{7}}{56}+\frac {2 i c^{6} x^{6}}{21}+\frac {9 c^{5} x^{5}}{40}-\frac {12 i c^{4} x^{4}}{35}-\frac {11 c^{3} x^{3}}{24}+\frac {24 i c^{2} x^{2}}{35}-\frac {24 i \ln \left (c^{2} x^{2}+1\right )}{35}-\frac {11 \arctan \left (c x \right )}{8}\right )}{c^{4}}\) | \(190\) |
derivativedivides | \(\frac {d^{4} a \left (\frac {1}{8} c^{8} x^{8}-\frac {4}{7} i c^{7} x^{7}-c^{6} x^{6}+\frac {4}{5} i c^{5} x^{5}+\frac {1}{4} c^{4} x^{4}\right )+d^{4} b \left (\frac {\arctan \left (c x \right ) c^{8} x^{8}}{8}-\frac {4 i \arctan \left (c x \right ) c^{7} x^{7}}{7}-\arctan \left (c x \right ) c^{6} x^{6}+\frac {4 i \arctan \left (c x \right ) c^{5} x^{5}}{5}+\frac {c^{4} x^{4} \arctan \left (c x \right )}{4}+\frac {11 c x}{8}-\frac {c^{7} x^{7}}{56}+\frac {2 i c^{6} x^{6}}{21}+\frac {9 c^{5} x^{5}}{40}-\frac {12 i c^{4} x^{4}}{35}-\frac {11 c^{3} x^{3}}{24}+\frac {24 i c^{2} x^{2}}{35}-\frac {24 i \ln \left (c^{2} x^{2}+1\right )}{35}-\frac {11 \arctan \left (c x \right )}{8}\right )}{c^{4}}\) | \(196\) |
default | \(\frac {d^{4} a \left (\frac {1}{8} c^{8} x^{8}-\frac {4}{7} i c^{7} x^{7}-c^{6} x^{6}+\frac {4}{5} i c^{5} x^{5}+\frac {1}{4} c^{4} x^{4}\right )+d^{4} b \left (\frac {\arctan \left (c x \right ) c^{8} x^{8}}{8}-\frac {4 i \arctan \left (c x \right ) c^{7} x^{7}}{7}-\arctan \left (c x \right ) c^{6} x^{6}+\frac {4 i \arctan \left (c x \right ) c^{5} x^{5}}{5}+\frac {c^{4} x^{4} \arctan \left (c x \right )}{4}+\frac {11 c x}{8}-\frac {c^{7} x^{7}}{56}+\frac {2 i c^{6} x^{6}}{21}+\frac {9 c^{5} x^{5}}{40}-\frac {12 i c^{4} x^{4}}{35}-\frac {11 c^{3} x^{3}}{24}+\frac {24 i c^{2} x^{2}}{35}-\frac {24 i \ln \left (c^{2} x^{2}+1\right )}{35}-\frac {11 \arctan \left (c x \right )}{8}\right )}{c^{4}}\) | \(196\) |
parallelrisch | \(-\frac {-105 b \,c^{8} d^{4} \arctan \left (c x \right ) x^{8}-80 i x^{6} b \,c^{6} d^{4}-105 a \,c^{8} d^{4} x^{8}+288 i x^{4} b \,c^{4} d^{4}+15 b \,c^{7} d^{4} x^{7}+480 i c^{7} b \,d^{4} \arctan \left (c x \right ) x^{7}+840 b \,c^{6} d^{4} \arctan \left (c x \right ) x^{6}+576 i b \,d^{4} \ln \left (c^{2} x^{2}+1\right )+840 a \,c^{6} d^{4} x^{6}-672 i c^{5} b \,d^{4} \arctan \left (c x \right ) x^{5}-189 b \,c^{5} d^{4} x^{5}-672 i x^{5} a \,c^{5} d^{4}-210 x^{4} \arctan \left (c x \right ) b \,c^{4} d^{4}-210 a \,c^{4} d^{4} x^{4}+385 b \,c^{3} d^{4} x^{3}-576 i x^{2} b \,c^{2} d^{4}+480 i x^{7} a \,c^{7} d^{4}-1155 b c \,d^{4} x +1155 b \,d^{4} \arctan \left (c x \right )}{840 c^{4}}\) | \(261\) |
risch | \(-\frac {i d^{4} c^{2} x^{6} b \ln \left (-i c x +1\right )}{2}+\frac {d^{4} c^{4} a \,x^{8}}{8}-\frac {4 i d^{4} c^{3} a \,x^{7}}{7}+\frac {2 d^{4} c^{3} b \,x^{7} \ln \left (-i c x +1\right )}{7}-\frac {b \,c^{3} d^{4} x^{7}}{56}-\frac {i d^{4} b \left (35 c^{4} x^{8}-160 i c^{3} x^{7}-280 c^{2} x^{6}+224 i c \,x^{5}+70 x^{4}\right ) \ln \left (i c x +1\right )}{560}-d^{4} c^{2} a \,x^{6}-\frac {24 i d^{4} b \ln \left (148225 c^{2} x^{2}+148225\right )}{35 c^{4}}-\frac {2 d^{4} c b \,x^{5} \ln \left (-i c x +1\right )}{5}+\frac {i d^{4} x^{4} b \ln \left (-i c x +1\right )}{8}+\frac {9 b c \,d^{4} x^{5}}{40}+\frac {i d^{4} c^{4} b \,x^{8} \ln \left (-i c x +1\right )}{16}+\frac {d^{4} a \,x^{4}}{4}+\frac {4 i d^{4} c a \,x^{5}}{5}+\frac {24 i b \,d^{4} x^{2}}{35 c^{2}}-\frac {11 b \,d^{4} x^{3}}{24 c}+\frac {2 i b \,c^{2} d^{4} x^{6}}{21}+\frac {11 b \,d^{4} x}{8 c^{3}}-\frac {11 b \,d^{4} \arctan \left (c x \right )}{8 c^{4}}-\frac {12 i b \,d^{4} x^{4}}{35}\) | \(324\) |
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Time = 0.26 (sec) , antiderivative size = 230, normalized size of antiderivative = 0.97 \[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\frac {210 \, a c^{8} d^{4} x^{8} - 30 \, {\left (32 i \, a + b\right )} c^{7} d^{4} x^{7} - 80 \, {\left (21 \, a - 2 i \, b\right )} c^{6} d^{4} x^{6} - 42 \, {\left (-32 i \, a - 9 \, b\right )} c^{5} d^{4} x^{5} + 12 \, {\left (35 \, a - 48 i \, b\right )} c^{4} d^{4} x^{4} - 770 \, b c^{3} d^{4} x^{3} + 1152 i \, b c^{2} d^{4} x^{2} + 2310 \, b c d^{4} x - 2307 i \, b d^{4} \log \left (\frac {c x + i}{c}\right ) + 3 i \, b d^{4} \log \left (\frac {c x - i}{c}\right ) - 3 \, {\left (-35 i \, b c^{8} d^{4} x^{8} - 160 \, b c^{7} d^{4} x^{7} + 280 i \, b c^{6} d^{4} x^{6} + 224 \, b c^{5} d^{4} x^{5} - 70 i \, b c^{4} d^{4} x^{4}\right )} \log \left (-\frac {c x + i}{c x - i}\right )}{1680 \, c^{4}} \]
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Time = 3.38 (sec) , antiderivative size = 389, normalized size of antiderivative = 1.63 \[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\frac {a c^{4} d^{4} x^{8}}{8} - \frac {11 b d^{4} x^{3}}{24 c} + \frac {24 i b d^{4} x^{2}}{35 c^{2}} + \frac {11 b d^{4} x}{8 c^{3}} + \frac {b d^{4} \left (\frac {i \log {\left (5893 b c d^{4} x - 5893 i b d^{4} \right )}}{560} - \frac {1471 i \log {\left (5893 b c d^{4} x + 5893 i b d^{4} \right )}}{1260}\right )}{c^{4}} + x^{7} \left (- \frac {4 i a c^{3} d^{4}}{7} - \frac {b c^{3} d^{4}}{56}\right ) + x^{6} \left (- a c^{2} d^{4} + \frac {2 i b c^{2} d^{4}}{21}\right ) + x^{5} \cdot \left (\frac {4 i a c d^{4}}{5} + \frac {9 b c d^{4}}{40}\right ) + x^{4} \left (\frac {a d^{4}}{4} - \frac {12 i b d^{4}}{35}\right ) + \left (- \frac {i b c^{4} d^{4} x^{8}}{16} - \frac {2 b c^{3} d^{4} x^{7}}{7} + \frac {i b c^{2} d^{4} x^{6}}{2} + \frac {2 b c d^{4} x^{5}}{5} - \frac {i b d^{4} x^{4}}{8}\right ) \log {\left (i c x + 1 \right )} + \frac {\left (315 i b c^{8} d^{4} x^{8} + 1440 b c^{7} d^{4} x^{7} - 2520 i b c^{6} d^{4} x^{6} - 2016 b c^{5} d^{4} x^{5} + 630 i b c^{4} d^{4} x^{4} - 1037 i b d^{4}\right ) \log {\left (- i c x + 1 \right )}}{5040 c^{4}} \]
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Time = 0.27 (sec) , antiderivative size = 337, normalized size of antiderivative = 1.42 \[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\frac {1}{8} \, a c^{4} d^{4} x^{8} - \frac {4}{7} i \, a c^{3} d^{4} x^{7} - a c^{2} d^{4} x^{6} + \frac {4}{5} i \, a c d^{4} x^{5} + \frac {1}{840} \, {\left (105 \, x^{8} \arctan \left (c x\right ) - c {\left (\frac {15 \, c^{6} x^{7} - 21 \, c^{4} x^{5} + 35 \, c^{2} x^{3} - 105 \, x}{c^{8}} + \frac {105 \, \arctan \left (c x\right )}{c^{9}}\right )}\right )} b c^{4} d^{4} - \frac {1}{21} i \, {\left (12 \, x^{7} \arctan \left (c x\right ) - c {\left (\frac {2 \, c^{4} x^{6} - 3 \, c^{2} x^{4} + 6 \, x^{2}}{c^{6}} - \frac {6 \, \log \left (c^{2} x^{2} + 1\right )}{c^{8}}\right )}\right )} b c^{3} d^{4} + \frac {1}{4} \, a d^{4} x^{4} - \frac {1}{15} \, {\left (15 \, x^{6} \arctan \left (c x\right ) - c {\left (\frac {3 \, c^{4} x^{5} - 5 \, c^{2} x^{3} + 15 \, x}{c^{6}} - \frac {15 \, \arctan \left (c x\right )}{c^{7}}\right )}\right )} b c^{2} d^{4} + \frac {1}{5} i \, {\left (4 \, x^{5} \arctan \left (c x\right ) - c {\left (\frac {c^{2} x^{4} - 2 \, x^{2}}{c^{4}} + \frac {2 \, \log \left (c^{2} x^{2} + 1\right )}{c^{6}}\right )}\right )} b c d^{4} + \frac {1}{12} \, {\left (3 \, x^{4} \arctan \left (c x\right ) - c {\left (\frac {c^{2} x^{3} - 3 \, x}{c^{4}} + \frac {3 \, \arctan \left (c x\right )}{c^{5}}\right )}\right )} b d^{4} \]
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\[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\int { {\left (i \, c d x + d\right )}^{4} {\left (b \arctan \left (c x\right ) + a\right )} x^{3} \,d x } \]
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Time = 2.78 (sec) , antiderivative size = 217, normalized size of antiderivative = 0.91 \[ \int x^3 (d+i c d x)^4 (a+b \arctan (c x)) \, dx=\frac {c^4\,d^4\,\left (105\,a\,x^8+105\,b\,x^8\,\mathrm {atan}\left (c\,x\right )\right )}{840}+\frac {d^4\,\left (210\,a\,x^4+210\,b\,x^4\,\mathrm {atan}\left (c\,x\right )-b\,x^4\,288{}\mathrm {i}\right )}{840}-\frac {\frac {d^4\,\left (1155\,b\,\mathrm {atan}\left (c\,x\right )+b\,\ln \left (c^2\,x^2+1\right )\,576{}\mathrm {i}\right )}{840}+\frac {11\,b\,c^3\,d^4\,x^3}{24}-\frac {11\,b\,c\,d^4\,x}{8}-\frac {b\,c^2\,d^4\,x^2\,24{}\mathrm {i}}{35}}{c^4}+\frac {c\,d^4\,\left (a\,x^5\,672{}\mathrm {i}+189\,b\,x^5+b\,x^5\,\mathrm {atan}\left (c\,x\right )\,672{}\mathrm {i}\right )}{840}-\frac {c^3\,d^4\,\left (a\,x^7\,480{}\mathrm {i}+15\,b\,x^7+b\,x^7\,\mathrm {atan}\left (c\,x\right )\,480{}\mathrm {i}\right )}{840}-\frac {c^2\,d^4\,\left (840\,a\,x^6+840\,b\,x^6\,\mathrm {atan}\left (c\,x\right )-b\,x^6\,80{}\mathrm {i}\right )}{840} \]
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